iron(III) oxides is formed when the iron reacts with oxygen
4Fe + 3O2>2Fe2O3
To calculate the moles :
According to stoichiometry :
3 moles of require 4 moles of
Thus 0.75 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 3 moles of give = 2 moles of
Thus 1 mole of give = of
Thus 107 g of will be produced from the given masses of both reactants.
Learn more about stoichiometry
↪↪When iron react with oxygen to form rust, each iron atom loses three electrons.↩↩
4Fe+ 3H2O+ 3O2 ● Fe2O3 + FeO(OH) +Fe(OH)3
4Fe+ 3O2>2 (Fe2O3)
a 136 g fe2o3
mass neitjer be created nor be destroyed
Rusting or corrosion take place
The iron & oxygen reacts to form a reddish - brown colour substance called asIRON OXIDE
Thus Sodium hydroxide turns red litmus into the blue. How satisfied are you with the answer ? This will ... After some time, she took both the solutions and checked them with litmus paper.
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